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youre doing [x^3 - x^2]/x, if x= 0 then it's 0/0
Quote:
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The expression 0/0 is an "indeterminate form". That does not simply mean that it is undefined; rather, it means that the limit of f(x)/g(x) is determined by the particular functions f and g as they both approach 0. As x approaches some number, the limit may approach any finite number, 0, ∞, or −∞, depending on the specific behavior of the functions. See l'Hôpital's rule.
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you stated it was IMPOSSIBLE, which was wrong, hence the logical loophole.