Quote:
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Originally Posted by SYRFox
Take the function:
f(x) = (1/x)(x^3 - x^2)
So: f(x) = (x^3/x) - (x^2/x)
= x² - x.
We proved that: (1/x)(x^3 - x^2) = x² -x.
But if x= 0:
-> x² - x = 0² - 0 = 0
-> (1/x)(x^3 - x^2) = (1/0)(0^3 - 0^2) : this is impossible (division per zero).
So these two functions are the same, but they're not the same (O_O)
OMG OMG WTF?!?
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If f(x) = x² - x
= f(x) = 0² - 0
then the division is the same. But 0² = 0.
You're dividing 0 by 0. Not possible unless 0 = x
OMG OMG WTF?!?